point h is the midpoint of side fk. for the triangles to be congruent by sss, what must be the value of x? 1…

point h is the midpoint of side fk. for the triangles to be congruent by sss, what must be the value of x? 1 3 6 8
Answer
Explanation:
Step1: Use the property of midpoint and SSS congruence
Since (H) is the midpoint of (FK), (FH = HK). For (\triangle FGH) and (\triangle KJH) to be congruent by SSS (Side - Side - Side), (FG=JK). We set up the equation (3x - 2=2x + 4).
Step2: Solve the linear equation
Subtract (2x) from both sides of the equation (3x - 2=2x + 4). (3x-2x-2=2x - 2x+4), which simplifies to (x-2 = 4). Then add (2) to both sides: (x-2 + 2=4 + 2).
Answer:
(x = 6), so the answer is (6).