which point on the number line shows the position of $sqrt{26}$? point a point b point c point d

Explanation:

Step1: Find the range of $\sqrt{26}$

We know that $5^2=25$ and $6^2 = 36$. Since $25<26<36$, then $5<\sqrt{26}<6$.

Step2: Compare $\sqrt{26}$ with $5.5$

Calculate $5.5^2=5.5\times5.5 = 30.25$. Since $26<30.25$, then $\sqrt{26}<5.5$.

Answer:

point B