point b is a point of tangency. find the radius r of ⊙c.

point b is a point of tangency. find the radius r of ⊙c.
Answer
Answer:
18
Explanation:
Step1: Apply tangent - radius property
Since point $B$ is a point of tangency, $\angle ABC = 90^{\circ}$, and $\triangle ABC$ is a right - triangle.
Step2: Use the Pythagorean theorem
In right - triangle $\triangle ABC$, by the Pythagorean theorem $AC^{2}=AB^{2}+BC^{2}$. Here, $AC=r + 16$, $AB = 24$, and $BC=r$. So, $(r + 16)^{2}=24^{2}+r^{2}$.
Step3: Expand the left - hand side
Expand $(r + 16)^{2}$: $r^{2}+32r+256=576+r^{2}$.
Step4: Simplify the equation
Subtract $r^{2}$ from both sides of the equation: $32r+256 = 576$.
Step5: Solve for $r$
Subtract 256 from both sides: $32r=576 - 256=320$. Then, divide both sides by 32: $r=\frac{320}{32}=18$.