which point - slope equation represents a line that passes through (3, -2) with a slope of…

which point - slope equation represents a line that passes through (3, -2) with a slope of $-\frac{4}{5}$?\n$y - 3=-\frac{4}{5}(x + 2)$\n$y - 2=\frac{4}{5}(x - 3)$\n$y + 2=-\frac{4}{5}(x - 3)$\n$y + 3=\frac{4}{5}(x + 2)$

which point - slope equation represents a line that passes through (3, -2) with a slope of $-\frac{4}{5}$?\n$y - 3=-\frac{4}{5}(x + 2)$\n$y - 2=\frac{4}{5}(x - 3)$\n$y + 2=-\frac{4}{5}(x - 3)$\n$y + 3=\frac{4}{5}(x + 2)$

Answer

Explanation:

Step1: Recall point - slope formula

The point - slope form of a line is $y - y_1=m(x - x_1)$, where $(x_1,y_1)$ is a point on the line and $m$ is the slope.

Step2: Identify values of $x_1$, $y_1$ and $m$

Given the point $(3,-2)$ and slope $m =-\frac{4}{5}$, we have $x_1 = 3$, $y_1=-2$.

Step3: Substitute values into formula

Substituting into $y - y_1=m(x - x_1)$ gives $y-(-2)=-\frac{4}{5}(x - 3)$, which simplifies to $y + 2=-\frac{4}{5}(x - 3)$.

Answer:

C. $y + 2=-\frac{4}{5}(x - 3)$