the point - slope form of the equation of the line that passes through (-4, -3) and (12, 1) is y…

the point - slope form of the equation of the line that passes through (-4, -3) and (12, 1) is y - 1=\frac{1}{4}(x - 12). what is the standard form of the equation for this line?\no x - 4y = 8\no x - 4y = 2\no 4x - y = 8\no 4x - y = 2

the point - slope form of the equation of the line that passes through (-4, -3) and (12, 1) is y - 1=\frac{1}{4}(x - 12). what is the standard form of the equation for this line?\no x - 4y = 8\no x - 4y = 2\no 4x - y = 8\no 4x - y = 2

Answer

Answer:

A. $x - 4y = 8$

Explanation:

Step1: Expand la ecuación dada

Comenzamos con $y - 1=\frac{1}{4}(x - 12)$. Expandimos el lado derecho: $y - 1=\frac{1}{4}x-3$.

Step2: Pasar términos a un lado

Movemos todos los términos a un lado para obtener la forma estándar $Ax + By=C$. Restamos $\frac{1}{4}x$ de ambos lados y sumamos 1 a ambos lados: $-\frac{1}{4}x+y=-3 + 1$.

Step3: Eliminar la fracción

Multiplicamos toda la ecuación por - 4 para eliminar la fracción. Obtenemos $x-4y = 8$.