the point - slope form of the equation of a line that passes through points (8, 4) and (0, 2) is $y…

the point - slope form of the equation of a line that passes through points (8, 4) and (0, 2) is $y - 4=\frac{1}{4}(x - 8)$. what is the slope - intercept form of the equation for this line?\n$y=\frac{1}{4}x - 12$\n$y=\frac{1}{4}x - 4$\n$y=\frac{1}{4}x + 2$\n$y=\frac{1}{4}x + 6$

the point - slope form of the equation of a line that passes through points (8, 4) and (0, 2) is $y - 4=\frac{1}{4}(x - 8)$. what is the slope - intercept form of the equation for this line?\n$y=\frac{1}{4}x - 12$\n$y=\frac{1}{4}x - 4$\n$y=\frac{1}{4}x + 2$\n$y=\frac{1}{4}x + 6$

Answer

Explanation:

Step1: Expand the right - hand side

Expand $\frac{1}{4}(x - 8)$ using the distributive property $a(b - c)=ab - ac$. Here $a=\frac{1}{4}$, $b = x$, $c = 8$. So $\frac{1}{4}(x - 8)=\frac{1}{4}x-2$. The equation becomes $y - 4=\frac{1}{4}x-2$.

Step2: Isolate y

Add 4 to both sides of the equation $y - 4=\frac{1}{4}x-2$. We get $y=\frac{1}{4}x-2 + 4$.

Step3: Simplify the right - hand side

Simplify $\frac{1}{4}x-2 + 4$ to $\frac{1}{4}x+2$.

Answer:

C. $y=\frac{1}{4}x + 2$