the point - slope form of the equation of the line that passes through (-9, -2) and (1, 3) is y - 3 = 1/2(x…
the point - slope form of the equation of the line that passes through (-9, -2) and (1, 3) is y - 3 = 1/2(x - 1). what is the slope - intercept form of the equation for this line?\no y = 1/2x + 2\no y = 1/2x - 4\no y = 1/2x + 5/2\no y = 1/2x - 7/2
Answer
Explanation:
Step1: Expand the point - slope form
Start with $y - 3=\frac{1}{2}(x - 1)$. Use the distributive property $a(b - c)=ab-ac$. So, $y-3=\frac{1}{2}x-\frac{1}{2}$.
Step2: Isolate y
Add 3 to both sides of the equation. $y=\frac{1}{2}x-\frac{1}{2}+3$. Since $3=\frac{6}{2}$, then $y=\frac{1}{2}x-\frac{1}{2}+\frac{6}{2}=\frac{1}{2}x+\frac{- 1 + 6}{2}=\frac{1}{2}x+\frac{5}{2}$.
Answer:
C. $y=\frac{1}{2}x+\frac{5}{2}$