the polynomial $x^{3}+8$ is equal to\n$(x + 2)(x^{2}-2x + 4)$\n$(x - 2)(x^{2}+2x + 4)$\n$(x + 2)(x^{2}-2x +…

the polynomial $x^{3}+8$ is equal to\n$(x + 2)(x^{2}-2x + 4)$\n$(x - 2)(x^{2}+2x + 4)$\n$(x + 2)(x^{2}-2x + 8)$\n$(x - 2)(x^{2}+2x + 8)$

the polynomial $x^{3}+8$ is equal to\n$(x + 2)(x^{2}-2x + 4)$\n$(x - 2)(x^{2}+2x + 4)$\n$(x + 2)(x^{2}-2x + 8)$\n$(x - 2)(x^{2}+2x + 8)$

Answer

Answer:

A. ((x + 2)(x^{2}-2x + 4))

Explanation:

Step1: Aplicar la fórmula de suma de cubos

La fórmula para (a^{3}+b^{3}=(a + b)(a^{2}-ab + b^{2})). Aquí (x^{3}+8=x^{3}+2^{3}), donde (a = x) y (b = 2).

Step2: Sustituir valores

Sustituyendo (a=x) y (b = 2) en la fórmula (a^{3}+b^{3}=(a + b)(a^{2}-ab + b^{2})), obtenemos ((x + 2)(x^{2}-2x+4)).