a polynomial function has a root of -5 with multiplicity 3, a root of 1 with multiplicity 2, and a root of 3…

a polynomial function has a root of -5 with multiplicity 3, a root of 1 with multiplicity 2, and a root of 3 with multiplicity 7. if the function has a negative leading coefficient and is of even degree, which statement about the graph is true?\nthe graph of the function is positive on (-∞, -5).\nthe graph of the function is negative on (-5, 3).\nthe graph of the function is positive on (-∞, 1).\nthe graph of the function is negative on (3, ∞).
Answer
Answer:
The graph of the function is negative on $(3,\infty)$.
Explanation:
Step1: Determine the degree of the polynomial
The degree is $3 + 2+7=12$ (sum of multiplicities).
Step2: Analyze end - behavior
Since the leading coefficient $a<0$ and degree $n = 12$ (even), as $x\to\pm\infty$, $y\to-\infty$.
Step3: Consider the roots
The roots are $x=-5$ (multiplicity 3), $x = 1$ (multiplicity 2), $x = 3$ (multiplicity 7). The graph crosses the $x$ - axis at odd - multiplicity roots ($x=-5$ and $x = 3$) and touches at even - multiplicity root ($x = 1$).
Step4: Test intervals
For $x>3$, since the end - behavior as $x\to\infty$ is $y\to-\infty$, the graph is negative on $(3,\infty)$.