what are the possible values of x if (4x - 5)^2 = 49? check all that apply.\n-\\frac{4}{5}\n-\\frac{1}{2}\n3\…
what are the possible values of x if (4x - 5)^2 = 49? check all that apply.\n-\\frac{4}{5}\n-\\frac{1}{2}\n3\n5\n7
Answer
Explanation:
Step1: Take square - root of both sides
Take the square - root of both sides of the equation $(4x - 5)^2=49$. We get $4x−5=\pm\sqrt{49}$, so $4x - 5=\pm7$.
Step2: Solve for $x$ when $4x - 5 = 7$
Add 5 to both sides: $4x=7 + 5$, so $4x=12$. Then divide both sides by 4: $x=\frac{12}{4}=3$.
Step3: Solve for $x$ when $4x - 5=-7$
Add 5 to both sides: $4x=-7 + 5$, so $4x=-2$. Then divide both sides by 4: $x=\frac{-2}{4}=-\frac{1}{2}$.
Answer:
B. $-\frac{1}{2}$, C. 3