5 which problem has a sum or difference that is equal to $1\\frac{2}{9}-3\\frac{1}{3}$?\na…

5 which problem has a sum or difference that is equal to $1\\frac{2}{9}-3\\frac{1}{3}$?\na. $-3\\frac{7}{9}+1\\frac{2}{3}$\nb. $\\frac{5}{9}-2\\frac{4}{9}$\nc. $-1\\frac{2}{9}+3\\frac{1}{3}$\nd. $-1\\frac{7}{9}+\\frac{1}{3}$

5 which problem has a sum or difference that is equal to $1\\frac{2}{9}-3\\frac{1}{3}$?\na. $-3\\frac{7}{9}+1\\frac{2}{3}$\nb. $\\frac{5}{9}-2\\frac{4}{9}$\nc. $-1\\frac{2}{9}+3\\frac{1}{3}$\nd. $-1\\frac{7}{9}+\\frac{1}{3}$

Answer

Explanation:

Step1: Rewrite mixed - numbers as improper fractions

$1\frac{2}{9}=\frac{9\times1 + 2}{9}=\frac{11}{9}$, $3\frac{1}{3}=\frac{3\times3+1}{3}=\frac{10}{3}=\frac{30}{9}$, so $1\frac{2}{9}-3\frac{1}{3}=\frac{11}{9}-\frac{30}{9}=-\frac{19}{9}$.

Step2: Rewrite options as improper fractions

Option A: $-3\frac{7}{9}+1\frac{2}{3}=-\frac{3\times9 + 7}{9}+\frac{1\times3+2}{3}=-\frac{34}{9}+\frac{5}{3}=-\frac{34}{9}+\frac{15}{9}=-\frac{19}{9}$.

Answer:

A. $-3\frac{7}{9}+1\frac{2}{3}$