what is the product of (2p + 7)(3p² + 4p - 3)?\n6p³ + 29p² - 34p + 21\n6p³ + 29p² - 22p + 21\n6p³ + 29p² +…
what is the product of (2p + 7)(3p² + 4p - 3)?\n6p³ + 29p² - 34p + 21\n6p³ + 29p² - 22p + 21\n6p³ + 29p² + 22p - 21\n6p³ + 29p² + 34p - 21
Answer
Explanation:
Step1: Use distributive property
$(2p + 7)(3p^{2}+4p - 3)=2p(3p^{2}+4p - 3)+7(3p^{2}+4p - 3)$
Step2: Multiply each term
$2p(3p^{2}+4p - 3)=2p\times3p^{2}+2p\times4p-2p\times3 = 6p^{3}+8p^{2}-6p$ $7(3p^{2}+4p - 3)=7\times3p^{2}+7\times4p-7\times3=21p^{2}+28p - 21$
Step3: Combine like - terms
$(6p^{3}+8p^{2}-6p)+(21p^{2}+28p - 21)=6p^{3}+(8p^{2}+21p^{2})+( - 6p+28p)-21=6p^{3}+29p^{2}+22p - 21$
Answer:
C. $6p^{3}+29p^{2}+22p - 21$