what is the product?\n$(x - 3)(2x^{2}-5x + 1)$\n$2x^{3}-x^{2}+16x + 3$\n$2x^{3}-11x^{2}+16x +…

what is the product?\n$(x - 3)(2x^{2}-5x + 1)$\n$2x^{3}-x^{2}+16x + 3$\n$2x^{3}-11x^{2}+16x + 3$\n$2x^{3}-11x^{2}+16x - 3$\n$2x^{3}-x^{2}+16x - 3$

what is the product?\n$(x - 3)(2x^{2}-5x + 1)$\n$2x^{3}-x^{2}+16x + 3$\n$2x^{3}-11x^{2}+16x + 3$\n$2x^{3}-11x^{2}+16x - 3$\n$2x^{3}-x^{2}+16x - 3$

Answer

Explanation:

Step1: Use distributive property

Multiply (x) by each term in ((2x^{2}-5x + 1)) and (-3) by each term in ((2x^{2}-5x + 1)) [ \begin{align*} x(2x^{2}-5x + 1)-3(2x^{2}-5x + 1)&=(x\times2x^{2})-(x\times5x)+(x\times1)+(-3\times2x^{2})-(-3\times5x)+(-3\times1)\ &=2x^{3}-5x^{2}+x-6x^{2}+15x - 3 \end{align*} ]

Step2: Combine like - terms

Combine the (x^{2}) terms ((-5x^{2}-6x^{2}=-11x^{2})) and the (x) terms ((x + 15x=16x)) [2x^{3}-11x^{2}+16x-3]

Answer:

(2x^{3}-11x^{2}+16x - 3) (the third option)