what is the product of 3a + 5 and 2a² + 4a - 2?\n6a³ + 22a² + 14a - 10\n6a³ + 22a² + 26a - 10\n18a³ + 10a² +…
what is the product of 3a + 5 and 2a² + 4a - 2?\n6a³ + 22a² + 14a - 10\n6a³ + 22a² + 26a - 10\n18a³ + 10a² + 14a - 10\n28a³ + 14a - 10
Answer
Explanation:
Step1: Use distributive property
$(3a + 5)(2a^{2}+4a - 2)=3a(2a^{2}+4a - 2)+5(2a^{2}+4a - 2)$
Step2: Multiply each term
$3a(2a^{2}+4a - 2)=3a\times2a^{2}+3a\times4a-3a\times2 = 6a^{3}+12a^{2}-6a$ $5(2a^{2}+4a - 2)=5\times2a^{2}+5\times4a-5\times2=10a^{2}+20a - 10$
Step3: Combine like - terms
$(6a^{3}+12a^{2}-6a)+(10a^{2}+20a - 10)=6a^{3}+(12a^{2}+10a^{2})+( - 6a+20a)-10=6a^{3}+22a^{2}+14a - 10$
Answer:
$6a^{3}+22a^{2}+14a - 10$