what is the product? (-3s + 2t)(4s - t)\n-12s² - 2t²\n-12s² + 2t²\n-12s² + 8st - 2t²\n-12s² + 11st - 2t²

Answer:

D. $-12s^{2}+11st - 2t^{2}$

Explanation:

Step1: Appliquer la distributivité

$(-3s + 2t)(4s - t)=-3s\times(4s - t)+2t\times(4s - t)$

Step2: Multiplier chaque terme

$-3s\times(4s - t)=-3s\times4s+(-3s)\times(-t)=-12s^{2}+3st$ $2t\times(4s - t)=2t\times4s-2t\times t = 8st-2t^{2}$

Step3: Additionner les résultats

$(-12s^{2}+3st)+(8st - 2t^{2})=-12s^{2}+(3st + 8st)-2t^{2}=-12s^{2}+11st - 2t^{2}$