what is the product?\n(4y - 3)(2y² + 3y - 5)\n○ 8y³ + 3y + 15\n○ 8y³ - 23y + 15\n○ 8y³ - 6y² - 17y + 15\n○…
what is the product?\n(4y - 3)(2y² + 3y - 5)\n○ 8y³ + 3y + 15\n○ 8y³ - 23y + 15\n○ 8y³ - 6y² - 17y + 15\n○ 8y³ + 6y² - 29y + 15
Answer
Explanation:
Step1: Distribute each term in first binomial
$4y(2y^2 + 3y - 5) - 3(2y^2 + 3y - 5)$
Step2: Calculate each product
$8y^3 + 12y^2 - 20y - 6y^2 - 9y + 15$
Step3: Combine like terms
$8y^3 + (12y^2 - 6y^2) + (-20y - 9y) + 15 = 8y^3 + 6y^2 - 29y + 15$
Answer:
D. $8y^3 + 6y^2 - 29y + 15$