what is the product? (4y - 3)(2y^2 + 3y - 5) 8y^3 + 3y + 15 8y^3 - 23y + 15 8y^3 - 6y^2 - 17y + 15 8y^3 +…

Explanation:

Step1: Use distributive property

$(4y - 3)(2y^{2}+3y - 5)=4y(2y^{2}+3y - 5)-3(2y^{2}+3y - 5)$

Step2: Multiply each term

$4y(2y^{2}+3y - 5)=4y\times2y^{2}+4y\times3y-4y\times5 = 8y^{3}+12y^{2}-20y$ $ - 3(2y^{2}+3y - 5)=-3\times2y^{2}-3\times3y + 3\times5=-6y^{2}-9y + 15$

Step3: Combine like - terms

$(8y^{3}+12y^{2}-20y)+(-6y^{2}-9y + 15)=8y^{3}+(12y^{2}-6y^{2})+(-20y-9y)+15=8y^{3}+6y^{2}-29y + 15$

Answer:

$8y^{3}+6y^{2}-29y + 15$ (the fourth option)