what is the product? (5r + 2)(3r - 4) 15r² + 8 15r² - 8 15r² + 14r - 8 15r² - 14r - 8

Explanation:

Step1: Use FOIL method

$(5r + 2)(3r-4)=5r\times3r+5r\times(-4)+2\times3r + 2\times(-4)$

Step2: Calculate each product

$5r\times3r = 15r^{2}$, $5r\times(-4)=-20r$, $2\times3r = 6r$, $2\times(-4)=-8$

Step3: Combine like - terms

$15r^{2}-20r + 6r-8=15r^{2}+(-20r + 6r)-8=15r^{2}-14r - 8$

Answer:

$15r^{2}-14r - 8$