what is the product? (6r - 1)(-8r - 3) -48r² - 10r + 3 -48r² - 10r - 3 -48r² + 3 -48r² - 3

what is the product? (6r - 1)(-8r - 3) -48r² - 10r + 3 -48r² - 10r - 3 -48r² + 3 -48r² - 3
Answer
Explanation:
Step1: Use FOIL method
$(6r - 1)(-8r-3)=6r\times(-8r)+6r\times(-3)+(-1)\times(-8r)+(-1)\times(-3)$
Step2: Calculate each product
$6r\times(-8r)=-48r^{2}$, $6r\times(-3)=-18r$, $(-1)\times(-8r) = 8r$, $(-1)\times(-3)=3$
Step3: Combine like - terms
$-48r^{2}-18r + 8r+3=-48r^{2}+(-18r + 8r)+3=-48r^{2}-10r + 3$
Answer:
$-48r^{2}-10r + 3$