what is the product?\n$\frac{2y}{y - 3}cdot\frac{4y - 12}{2y + 6}$\n$\frac{2}{3}$\n$\frac{10}{9}$\n$\frac{4y}…

what is the product?\n$\frac{2y}{y - 3}cdot\frac{4y - 12}{2y + 6}$\n$\frac{2}{3}$\n$\frac{10}{9}$\n$\frac{4y}{y - 3}$\n$\frac{4y}{y + 3}$

what is the product?\n$\frac{2y}{y - 3}cdot\frac{4y - 12}{2y + 6}$\n$\frac{2}{3}$\n$\frac{10}{9}$\n$\frac{4y}{y - 3}$\n$\frac{4y}{y + 3}$

Answer

Explanation:

Step1: Factor the expressions

Factor (4y - 12) to (4(y - 3)) and (2y+6) to (2(y + 3)). The expression becomes (\frac{2y}{y - 3}\cdot\frac{4(y - 3)}{2(y + 3)}).

Step2: Cancel out common factors

Cancel out the common factors (2) and ((y - 3)) in the numerator and denominator. (\frac{2y}{y - 3}\cdot\frac{4(y - 3)}{2(y + 3)}=\frac{2y\cdot4}{2(y + 3)}). After cancel - ing, we get (\frac{4y}{y + 3}).

Answer:

(\frac{4y}{y + 3})