what is the product?\n$\frac{4n}{4n - 4}cdot\frac{n - 1}{n + 1}$\n$\frac{4n}{n + 1}$\n$\frac{n}{n +…

what is the product?\n$\frac{4n}{4n - 4}cdot\frac{n - 1}{n + 1}$\n$\frac{4n}{n + 1}$\n$\frac{n}{n + 1}$\n$\frac{1}{n + 1}$\n$\frac{4}{n + 1}$

what is the product?\n$\frac{4n}{4n - 4}cdot\frac{n - 1}{n + 1}$\n$\frac{4n}{n + 1}$\n$\frac{n}{n + 1}$\n$\frac{1}{n + 1}$\n$\frac{4}{n + 1}$

Answer

Explanation:

Step1: Factor the denominator

Factor $4n - 4$ as $4(n - 1)$. So the expression becomes $\frac{4n}{4(n - 1)}\cdot\frac{n - 1}{n + 1}$.

Step2: Cancel out common factors

Cancel out the common factors 4 and $(n - 1)$ in the numerator and denominator. We have $\frac{4n}{4(n - 1)}\cdot\frac{n - 1}{n + 1}=\frac{n}{n + 1}$.

Answer:

$\frac{n}{n + 1}$