product property:$log_b xy = log_b x + log_b y$write $log_7 (2 cdot 6) + log_7 3$ as a single log.$log_7…

product property:$log_b xy = log_b x + log_b y$write $log_7 (2 cdot 6) + log_7 3$ as a single log.$log_7 36$$log_7 15$$log_7 11$

product property:$log_b xy = log_b x + log_b y$write $log_7 (2 cdot 6) + log_7 3$ as a single log.$log_7 36$$log_7 15$$log_7 11$

Answer

Explanation:

Step1: Simplify inside first log

$\log_7(2 \cdot 6) = \log_7 12$

Step2: Apply log product property

$\log_7 12 + \log_7 3 = \log_7(12 \cdot 3)$

Step3: Calculate the product

$12 \cdot 3 = 36$

Answer:

$\log_7 36$