the product of two consecutive integers is 420. an equation is written in standard form to solve for the…

the product of two consecutive integers is 420. an equation is written in standard form to solve for the smaller integer by factoring. what is the constant of the quadratic expression in this equation? $x^{2}+x+square =0$

the product of two consecutive integers is 420. an equation is written in standard form to solve for the smaller integer by factoring. what is the constant of the quadratic expression in this equation? $x^{2}+x+square =0$

Answer

Explanation:

Step1: Let the smaller integer be $x$.

The larger consecutive integer is $x + 1$.

Step2: Set up the product - equation.

$x(x + 1)=420$.

Step3: Expand the left - hand side.

$x^{2}+x=420$.

Step4: Rewrite in standard quadratic form.

$x^{2}+x - 420=0$.

Answer:

$-420$