the product of two consecutive integers is 420. an equation is written in standard form to solve for the…

the product of two consecutive integers is 420. an equation is written in standard form to solve for the smaller integer by factoring. what is the constant of the quadratic expression in this equation? $x^{2}+x+square = 0$

the product of two consecutive integers is 420. an equation is written in standard form to solve for the smaller integer by factoring. what is the constant of the quadratic expression in this equation? $x^{2}+x+square = 0$

Answer

Explanation:

Step1: Definir los enteros consecutivos

Sea el entero más pequeño $x$, entonces el siguiente entero consecutivo es $x + 1$.

Step2: Escribir la ecuación

El producto de estos dos enteros es 420, entonces $x(x + 1)=420$.

Step3: Convertir a forma estándar

Expandir $x(x + 1)=420$ da $x^{2}+x=420$, y re - escribiéndola en la forma $ax^{2}+bx + c = 0$ obtenemos $x^{2}+x-420=0$.

Answer:

$-420$