the product of two consecutive positive integers is 812. what is the value of the lesser integer?\n7\n28\n58\…

Answer:

B. 28

Explanation:

Step1: Let the lesser integer be $x$.

Then the greater consecutive integer is $x + 1$.

Step2: Set up the equation.

$x(x + 1)=812$, which expands to $x^{2}+x - 812=0$.

Step3: Factor the quadratic equation.

We need to find two numbers that multiply to - 812 and add up to 1. The numbers are 29 and - 28. So, $(x + 29)(x - 28)=0$.

Step4: Solve for $x$.

Setting each factor equal to zero gives $x=-29$ or $x = 28$. Since we are looking for positive integers, we discard $x=-29$. So the lesser positive - integer is 28.