products of irrational square roots quick check\nrewrite the irrational square root \\( \\sqrt { 48 } \\) as…

products of irrational square roots quick check\nrewrite the irrational square root \\( \\sqrt { 48 } \\) as the product of an integer and another irrational square\nroot. (1 point)\n\\( 2 \\sqrt { 24 } \\)\n\\( 4 \\sqrt { 3 } \\)\n\\( 2 \\sqrt { 12 } \\)\n\\( 4 \\sqrt { 12 } \\)
Answer
Explanation:
Step1: Factorize 48
We know that (48 = 16\times3).
Step2: Use the property (\sqrt{ab}=\sqrt{a}\times\sqrt{b}) ((a = 16), (b = 3))
(\sqrt{48}=\sqrt{16\times3}=\sqrt{16}\times\sqrt{3}) Since (\sqrt{16}=4), then (\sqrt{48}=4\sqrt{3})
Answer:
(4\sqrt{3}) (corresponding to the option (4\sqrt{3}) if we assume the options are (2\sqrt{24}), (4\sqrt{3}), (2\sqrt{12}), (4\sqrt{12}) and we pick the correct one based on calculation)