the proof that $delta acb cong delta ecd$ is shown.\ngiven: $overline{ae}$ and $overline{db}$ bisect each…

the proof that $delta acb cong delta ecd$ is shown.\ngiven: $overline{ae}$ and $overline{db}$ bisect each other at c.\nprove: $delta acb cong delta ecd$\nwhat is the missing statement in the proof?\n$\bigcirc$ $angle bac cong angle dec$\n$\bigcirc$ $angle acd cong angle ecb$\n$\bigcirc$ $angle acb cong angle ecd$\n$\bigcirc$ $angle bca cong angle dca$

the proof that $delta acb cong delta ecd$ is shown.\ngiven: $overline{ae}$ and $overline{db}$ bisect each other at c.\nprove: $delta acb cong delta ecd$\nwhat is the missing statement in the proof?\n$\bigcirc$ $angle bac cong angle dec$\n$\bigcirc$ $angle acd cong angle ecb$\n$\bigcirc$ $angle acb cong angle ecd$\n$\bigcirc$ $angle bca cong angle dca$

Answer

Explanation:

Step1: Identify given bisect property

Since $\overline{AE}$ and $\overline{DB}$ bisect at $C$, we get $\overline{AC} \cong \overline{EC}$ and $\overline{BC} \cong \overline{DC}$.

Step2: Find vertical angles

Intersecting lines create congruent vertical angles. For lines $\overline{AE}$ and $\overline{DB}$, $\angle ACB$ and $\angle ECD$ are vertical angles.

Step3: Match to triangle congruence

To use SAS (Side-Angle-Side) congruence for $\triangle ACB \cong \triangle ECD$, we need the included angle between the congruent sides, which is $\angle ACB \cong \angle ECD$.

Answer:

$\boldsymbol{\angle ACB \cong \angle ECD}$