which quadratic equation is equivalent to $(x^{2}-1)^{2}-11(x^{2}-1)+24 = 0$?\n$u^{2}-11u + 24 = 0$ where…

which quadratic equation is equivalent to $(x^{2}-1)^{2}-11(x^{2}-1)+24 = 0$?\n$u^{2}-11u + 24 = 0$ where $u=(x^{2}-1)$\n$(u^{2})^{2}-11(u^{2})+24$ where $u=(x^{2}-1)$\n$u^{2}+1 - 11u + 24 = 0$ where $u=(x^{2}-1)$\n$(u^{2}-1)^{2}-11(u^{2}-1)+24$ where $u=(x^{2}-1)$

which quadratic equation is equivalent to $(x^{2}-1)^{2}-11(x^{2}-1)+24 = 0$?\n$u^{2}-11u + 24 = 0$ where $u=(x^{2}-1)$\n$(u^{2})^{2}-11(u^{2})+24$ where $u=(x^{2}-1)$\n$u^{2}+1 - 11u + 24 = 0$ where $u=(x^{2}-1)$\n$(u^{2}-1)^{2}-11(u^{2}-1)+24$ where $u=(x^{2}-1)$

Answer

Answer:

A. $u^{2}-11u + 24 = 0$ where $u=(x^{2}-1)$

Explanation:

Step1: Define substitution variable

Let $u = x^{2}-1$.

Step2: Substitute into equation

Substitute $u$ into $(x^{2}-1)^{2}-11(x^{2}-1)+24 = 0$. We get $u^{2}-11u + 24 = 0$.