question 31\nnot yet answered marked out of 2.00 flag question\nwhich of these numbers is a perfect…

planation:

Step1: Analyze option a

A perfect square is a number that can be written as (n^2) where (n) is an integer. For (49), since (7^2 = 49) ((n = 7) is an integer).

Step2: Analyze option b

First, (-\sqrt{9}=-3). A perfect square is non - negative. Because if (m^2=-3), then (m=\pm\sqrt{- 3}), which is not a real number (let alone an integer).

Step3: Analyze option c

For (7), if (n^2 = 7), then (n=\pm\sqrt{7}), and (\sqrt{7}\approx2.65) is not an integer.

Step4: Analyze option e

(\sqrt{36}=6). But a perfect square is of the form (n^2). Here (\sqrt{36}) is a square root result (a number, but not in the form of (n^2) for the context of this question's options. The number (36) is a perfect square ((6^2 = 36)), but (\sqrt{36}) is just (6)).

Answer:

A. 49