question: consider the function $y = 2sin(x)$ for $0^{circ}leq xleq360^{circ}$. 1. graph the function: plot…

question: consider the function $y = 2sin(x)$ for $0^{circ}leq xleq360^{circ}$. 1. graph the function: plot the function $y = 2sin(x)$ on a coordinate plane. label the x - axis as \angle (degrees)\ and the y - axis as \y - value\. mark the coordinates of all key points where the graph intersects the x - axis, reaches its maximum, or minimum within the given interval.

question: consider the function $y = 2sin(x)$ for $0^{circ}leq xleq360^{circ}$. 1. graph the function: plot the function $y = 2sin(x)$ on a coordinate plane. label the x - axis as \angle (degrees)\ and the y - axis as \y - value\. mark the coordinates of all key points where the graph intersects the x - axis, reaches its maximum, or minimum within the given interval.

Answer

Explanation:

Step1: 确定关键点

当(y = 0)时，(2\sin(x)=0)，(x = 0^{\circ},180^{\circ},360^{\circ})；当(\sin(x)=1)时，(y)取最大值(2)，此时(x = 90^{\circ})；当(\sin(x)= - 1)时，(y)取最小值(-2)，此时(x = 270^{\circ})。

Step2: 绘制图像

在坐标平面上，以“角度（度）”为(x)轴，“(y)值”为(y)轴，标出上述关键点并绘制(y = 2\sin(x))图像。

Answer:

按步骤绘制出(y = 2\sin(x))在(0^{\circ}\leq x\leq360^{\circ})的图像，关键点坐标为((0,0))，((90,2))，((180,0))，((270, - 2))，((360,0)) 。