question\nwhat is an equation of the line that passes through the points (-7, -4) and (6, -4)?

Answer:

$y = - 4$

Explanation:

Step1: Calculate the slope

The slope formula is $m=\frac{y_2 - y_1}{x_2 - x_1}$. Let $(x_1,y_1)=(-7,-4)$ and $(x_2,y_2)=(6,-4)$. Then $m=\frac{-4-(-4)}{6 - (-7)}=\frac{-4 + 4}{6+7}=0$.

Step2: Use the point - slope form

The point - slope form of a line is $y - y_1=m(x - x_1)$. Using the point $(-7,-4)$ and $m = 0$, we have $y-(-4)=0\times(x - (-7))$.

Step3: Simplify the equation

$y + 4=0$, so $y=-4$.