question\nexpand and state your answer as a polynomial in standard form.\n$(2x - y^{4})^{2}$

Explanation:

Step1: Apply the formula $(a - b)^2=a^2-2ab + b^2$

Here $a = 2x$ and $b=y^{4}$, so $(2x - y^{4})^2=(2x)^2-2\times(2x)\times y^{4}+(y^{4})^2$.

Step2: Simplify each term

$(2x)^2 = 4x^{2}$, $2\times(2x)\times y^{4}=4xy^{4}$, and $(y^{4})^2=y^{8}$. So the expanded form is $4x^{2}-4xy^{4}+y^{8}$.

Answer:

$4x^{2}-4xy^{4}+y^{8}$