question\nexpress in simplest radical form.\n$sqrt{147}$

Explanation:

Step1: Prime - factorize 147

$147 = 3\times49=3\times7\times7$

Step2: Rewrite the square - root

$\sqrt{147}=\sqrt{3\times7^{2}}$

Step3: Apply the square - root property $\sqrt{ab}=\sqrt{a}\cdot\sqrt{b}$ ($a = 3$, $b = 7^{2}$)

$\sqrt{3\times7^{2}}=\sqrt{3}\cdot\sqrt{7^{2}}$

Step4: Simplify $\sqrt{7^{2}}$

$\sqrt{3}\cdot\sqrt{7^{2}} = 7\sqrt{3}$

Answer:

$7\sqrt{3}$