question\nexpress in simplest radical form.\n$sqrt{63}$

Explanation:

Step1: Factor the number inside the square - root

We know that $63 = 9\times7$. So, $\sqrt{63}=\sqrt{9\times7}$.

Step2: Use the property of square - roots $\sqrt{ab}=\sqrt{a}\cdot\sqrt{b}$ ($a = 9$, $b = 7$)

$\sqrt{9\times7}=\sqrt{9}\cdot\sqrt{7}$.

Step3: Simplify $\sqrt{9}$

Since $\sqrt{9}=3$, then $\sqrt{9}\cdot\sqrt{7}=3\sqrt{7}$.

Answer:

$3\sqrt{7}$