question\nfactor.\n$x^{2}+3x - 18$

Explanation:

Step1: Find two numbers

We need two numbers that multiply to - 18 and add up to 3. The numbers are 6 and - 3 since $6\times(-3)=-18$ and $6+( - 3)=3$.

Step2: Rewrite the middle - term

Rewrite the quadratic expression $x^{2}+3x - 18$ as $x^{2}+6x-3x - 18$.

Step3: Group the terms

Group the terms: $(x^{2}+6x)+(-3x - 18)$.

Step4: Factor out the GCF from each group

Factor out the GCF from each group. From $x^{2}+6x$, the GCF is $x$, so we get $x(x + 6)$. From $-3x - 18$, the GCF is - 3, so we get $-3(x + 6)$.

Step5: Factor out the common binomial factor

Factor out the common binomial factor $(x + 6)$: $(x + 6)(x-3)$.

Answer:

$(x + 6)(x - 3)$