question\nfactor.\n$x^{2}+6x - 27$

Explanation:

Step1: Find two numbers

We need two numbers that multiply to -27 and add up to 6. The numbers are 9 and - 3 since (9\times(-3)=-27) and (9+( - 3)=6).

Step2: Rewrite the middle - term

Rewrite (x^{2}+6x - 27) as (x^{2}+9x-3x - 27).

Step3: Group the terms

Group the terms: ((x^{2}+9x)-(3x + 27)).

Step4: Factor out the GCF from each group

Factor out (x) from the first group and 3 from the second group: (x(x + 9)-3(x + 9)).

Step5: Factor out the common binomial factor

Factor out ((x + 9)) to get ((x + 9)(x-3)).

Answer:

((x + 9)(x - 3))