question factor completely. 28x^{3}y^{7}z^{2}-7xy^{4}
question factor completely. 28x^{3}y^{7}z^{2}-7xy^{4}
Answer
Explanation:
Step1: Find the GCF of coefficients and variables
The GCF of 28 and 7 is 7. For variables, the GCF of $x^{3}y^{7}z^{2}$ and $xy^{4}$ is $xy^{4}$. So the GCF of the two - terms is $7xy^{4}$.
Step2: Factor out the GCF
$28x^{3}y^{7}z^{2}-7xy^{4}=7xy^{4}(4x^{2}y^{3}z^{2} - 1)$
Answer:
$7xy^{4}(4x^{2}y^{3}z^{2}-1)$