question\nfind the slope of a line perpendicular to the line whose equation is 10x - 12y = -24. fully…

question\nfind the slope of a line perpendicular to the line whose equation is 10x - 12y = -24. fully simplify your answer.\nanswer attempt 1 out of 2\nsubmit answer
Answer
Explanation:
Step1: Convert the given equation to slope - intercept form ($y = mx + b$)
Starting with (10x-12y=-24). Subtract (10x) from both sides: (-12y=-10x - 24). Divide each term by (-12): (y=\frac{10}{12}x + 2=\frac{5}{6}x+2). The slope of the given line ((m_1)) is (\frac{5}{6}).
Step2: Use the perpendicular slope formula ((m_2=-\frac{1}{m_1}))
Since (m_1 = \frac{5}{6}), then (m_2=-\frac{6}{5}).
Answer:
(-\frac{6}{5})