question graph the inequality on the axes below. 2x + 3y ≤ 3

Explanation:

Step1: Find the x - intercept

Set (y = 0) in the equation (2x+3y = 3). Then (2x=3), so (x=\frac{3}{2}=1.5). The x - intercept is the point ((1.5,0)).

Step2: Find the y - intercept

Set (x = 0) in the equation (2x + 3y=3). Then (3y=3), so (y = 1). The y - intercept is the point ((0,1)).

Step3: Draw the line

Draw a solid line (since the inequality is (\leq)) passing through the points ((1.5,0)) and ((0,1)).

Step4: Test a point

Test the point ((0,0)) in the inequality (2x+3y\leq3). Substitute (x = 0) and (y = 0): (2(0)+3(0)=0\leq3). Since this is true, shade the region that contains the point ((0,0)).

Answer:

Draw a solid line passing through ((1.5,0)) and ((0,1)) and shade the region below (including the line) the line that contains the origin ((0,0)).