question 2(multiple choice worth 1 points) (solving compound inequalities mc) find the solution for c in the…

question 2(multiple choice worth 1 points) (solving compound inequalities mc) find the solution for c in the compound inequality -4c + 14 ≤ 26 and 26 ≥ 6c - 10. {c | -4 ≤ c ≤ 6} {c | -10 ≤ c ≤ 4} {c | -3 ≥ c ≤ 6} {c | -3 ≤ c ≤ 6}

question 2(multiple choice worth 1 points) (solving compound inequalities mc) find the solution for c in the compound inequality -4c + 14 ≤ 26 and 26 ≥ 6c - 10. {c | -4 ≤ c ≤ 6} {c | -10 ≤ c ≤ 4} {c | -3 ≥ c ≤ 6} {c | -3 ≤ c ≤ 6}

Answer

Explanation:

Step1: Solve the first inequality

Starting with $-4c + 14\leq26$. Subtract 14 from both sides: $-4c\leq26 - 14$, so $-4c\leq12$. Divide both sides by - 4 and reverse the inequality sign (since dividing by a negative number), we get $c\geq - 3$.

Step2: Solve the second inequality

Starting with $26\geq6c - 10$. Add 10 to both sides: $26+10\geq6c$, so $36\geq6c$. Divide both sides by 6, we get $6\geq c$ or $c\leq6$.

Answer:

${c|-3\leq c\leq6}$