question 3 (1 point) ✓ saved\nlisten\nuse long division to divide.\n$(4x^{3}-17x^{2}-1x + 29)div(x - 4)$\na)…

question 3 (1 point) ✓ saved\nlisten\nuse long division to divide.\n$(4x^{3}-17x^{2}-1x + 29)div(x - 4)$\na) $4x^{2}-33x - 364$\nb) $4x^{2}-33x + 131-\frac{495}{x - 4}$\nc) $4x^{2}-1x - 5+\frac{9}{x - 4}$\nd) $4x^{2}-1x + 4$
Answer
Explanation:
Step1: Divide the leading term of the dividend by the leading term of the divisor
Divide (4x^{3}) by (x). (\frac{4x^{3}}{x}=4x^{2}) Multiply ((x - 4)) by (4x^{2}): (4x^{2}(x - 4)=4x^{3}-16x^{2}) Subtract from the dividend: ((4x^{3}-17x^{2}-x + 29)-(4x^{3}-16x^{2})=-x^{2}-x+29)
Step2: Repeat the process for the new dividend (-x^{2}-x + 29)
Divide (-x^{2}) by (x). (\frac{-x^{2}}{x}=-x) Multiply ((x - 4)) by (-x): (-x(x - 4)=-x^{2}+4x) Subtract: ((-x^{2}-x + 29)-(-x^{2}+4x)=-5x+29)
Step3: Repeat the process for the new dividend (-5x + 29)
Divide (-5x) by (x). (\frac{-5x}{x}=-5) Multiply ((x - 4)) by (-5): (-5(x - 4)=-5x + 20) Subtract: ((-5x+29)-(-5x + 20)=9)
Answer:
C. (4x^{2}-x - 5+\frac{9}{x - 4})