question\nsolve for x. round to the nearest tenth of a degree, if necessary.

question\nsolve for x. round to the nearest tenth of a degree, if necessary.
Answer
Explanation:
Step1: Identify the trigonometric ratio
In right - triangle $PQR$ with right - angle at $Q$, we know the opposite side ($QR = 3.3$) and the hypotenuse ($PR = 6$) with respect to the angle $x$. We use the sine ratio, $\sin x=\frac{\text{opposite}}{\text{hypotenuse}}$. So, $\sin x=\frac{3.3}{6}$.
Step2: Calculate the value of $\sin x$
$\sin x=\frac{3.3}{6}=0.55$.
Step3: Find the value of $x$
We know that if $\sin x = 0.55$, then $x=\sin^{- 1}(0.55)$. Using a calculator, $x=\sin^{-1}(0.55)\approx33.4^{\circ}$.
Answer:
$33.4^{\circ}$