question\nsolve for x. round to the nearest tenth of a degree, if necessary.

question\nsolve for x. round to the nearest tenth of a degree, if necessary.

question\nsolve for x. round to the nearest tenth of a degree, if necessary.

Answer

Explanation:

Step1: Identify the trigonometric ratio

In right - triangle $PQR$ with right - angle at $Q$, we know the opposite side ($QR = 3.3$) and the hypotenuse ($PR = 6$) with respect to the angle $x$. We use the sine ratio, $\sin x=\frac{\text{opposite}}{\text{hypotenuse}}$. So, $\sin x=\frac{3.3}{6}$.

Step2: Calculate the value of $\sin x$

$\sin x=\frac{3.3}{6}=0.55$.

Step3: Find the value of $x$

We know that if $\sin x = 0.55$, then $x=\sin^{- 1}(0.55)$. Using a calculator, $x=\sin^{-1}(0.55)\approx33.4^{\circ}$.

Answer:

$33.4^{\circ}$