question\nwrite an exponential function in the form $y = ab^x$ that goes through the points $(0, 13)$ and…

question\nwrite an exponential function in the form $y = ab^x$ that goes through the points $(0, 13)$ and $(8, 3328)$. \nshow examples
Answer
Explanation:
Step1: Solve for $a$ using $(0,13)$
Substitute $x=0, y=13$ into $y=ab^x$: $13 = ab^0$ Since $b^0=1$, we get $a=13$.
Step2: Substitute $a$ and $(8,3328)$
Substitute $a=13$, $x=8$, $y=3328$ into $y=ab^x$: $3328 = 13b^8$
Step3: Isolate $b^8$
Divide both sides by 13: $\frac{3328}{13}=b^8$ $256 = b^8$
Step4: Solve for $b$
Take the 8th root of both sides: $b = \sqrt[8]{256}$ Since $2^8=256$, $b=2$.
Answer:
$y=13(2)^x$