what is the quotient?\n$\frac{(-7)^{2}}{(-7)^{-1}}$\n-343\n-7\n7\n343

Explanation:

Step1: Apply exponent - division rule

According to the rule $\frac{a^m}{a^n}=a^{m - n}$, for $\frac{(-7)^2}{(-7)^{-1}}$, we have $m = 2$ and $n=-1$. So $(-7)^{2-(-1)}$.

Step2: Simplify the exponent

$2-(-1)=2 + 1=3$. So the expression becomes $(-7)^3$.

Step3: Calculate the result

$(-7)^3=(-7)\times(-7)\times(-7)=-343$.

Answer:

-343