what is the quotient of $\frac{-8x^{6}}{4x^{-3}}$?\n$\frac{x^{9}}{32}$\n$4x^{9}$\n$-\frac{12}{x^{2}}$\n$-2x^{…
what is the quotient of $\frac{-8x^{6}}{4x^{-3}}$?\n$\frac{x^{9}}{32}$\n$4x^{9}$\n$-\frac{12}{x^{2}}$\n$-2x^{9}$
Answer
Explanation:
Step1: Divide the coefficients
Divide -8 by 4: $\frac{-8}{4}=-2$.
Step2: Divide the variables
Use the rule $\frac{x^m}{x^n}=x^{m - n}$. Here $m = 6$ and $n=-3$, so $\frac{x^{6}}{x^{-3}}=x^{6-(-3)}=x^{6 + 3}=x^{9}$.
Step3: Combine the results
Multiply the result of coefficient - division and variable - division: $-2\times x^{9}=-2x^{9}$.
Answer:
D. $-2x^{9}$