what is the quotient?\n$\frac{7^{-4}}{7^{-9}}$\n$\frac{1}{7^{13}}$\n$\frac{1}{7^{5}}$\n$7^{5}$\n$7^{13}$
what is the quotient?\n$\frac{7^{-4}}{7^{-9}}$\n$\frac{1}{7^{13}}$\n$\frac{1}{7^{5}}$\n$7^{5}$\n$7^{13}$
Answer
Explanation:
Step1: Apply exponent - division rule
According to the rule $\frac{a^m}{a^n}=a^{m - n}$, for $\frac{7^{-4}}{7^{-9}}$, we have $a = 7$, $m=-4$, and $n = - 9$. So, $7^{-4-(-9)}$.
Step2: Simplify the exponent
$-4-(-9)=-4 + 9=5$. So the result is $7^{5}$.
Answer:
$7^{5}$