what is the radius of a circle whose equation is (x + 5)^2 + (y - 3)^2 = 4^2?\n2 units\n4 units\n8 units\n16…

Explanation:

Step1: Recall circle - equation formula

The standard form of a circle's equation is $(x - a)^2+(y - b)^2=r^2$, where $(a,b)$ is the center of the circle and $r$ is the radius.

Step2: Identify the radius from the given equation

Given the equation $(x + 5)^2+(y - 3)^2=4^2$. Comparing it with the standard form $(x - a)^2+(y - b)^2=r^2$, we can see that $r^2 = 4^2$.

Step3: Solve for the radius

Taking the square - root of both sides of the equation $r^2 = 4^2$, we get $r = 4$ (we consider the positive value since the radius is a non - negative quantity).

Answer:

4 units