what is the range of the function y = e^4x?\no y<0\no y>0\no y<4\no y>4

Explanation:

Step1: Recall exponential - function properties

The general form of an exponential function is $y = a^{x}$, where $a>0,a\neq1$. For the natural - exponential function $y = e^{x}$, the base $e\approx2.718>0$.

Step2: Analyze the given function $y = e^{4x}$

Let $t = 4x$. Then $y = e^{t}$. Since $t$ can take on all real - number values (i.e., $t\in(-\infty,\infty)$), and the exponential function $y = e^{t}$ is always positive for all real values of $t$. That is, for any real number $t$, $e^{t}>0$.

Answer:

B. $y > 0$