what is the range of the function $y = sqrt{x + 5}$?\n$ygeq - 5$\n$ygeq0$\n$ygeqsqrt{5}$\n$ygeq5$

Answer:

B. $y\geq0$

Explanation:

Step1: Recall square - root property

The square - root function $\sqrt{u}$ is defined such that $\sqrt{u}\geq0$ for all $u\geq0$ in the real - number system. In the function $y = \sqrt{x + 5}$, the expression under the square root is $u=x + 5$.

Step2: Determine range

Since the square root of a non - negative number $x+5$ (i.e., $x+5\geq0$) is always non - negative, the value of $y=\sqrt{x + 5}\geq0$. So the range of the function $y=\sqrt{x + 5}$ is $y\geq0$.