raphael graphed the functions ( g(x)=x + 2 ) and ( f(x)=x - 1 ). how many units below the ( y )-intercept of…

raphael graphed the functions ( g(x)=x + 2 ) and ( f(x)=x - 1 ). how many units below the ( y )-intercept of ( g(x) ) is the ( y )-intercept of ( f(x) )?

raphael graphed the functions ( g(x)=x + 2 ) and ( f(x)=x - 1 ). how many units below the ( y )-intercept of ( g(x) ) is the ( y )-intercept of ( f(x) )?

Answer

Explanation:

Step1: Find y - intercepts

For (g(x)=x + 2), when (x = 0), (y=0 + 2=2). So (y) - intercept of (g(x)) is (2). For (f(x)=x-1), when (x = 0), (y=0-1=-1). So (y) - intercept of (f(x)) is (-1).

Step2: Calculate the difference

The difference between the (y) - intercept of (g(x)) and (y) - intercept of (f(x)) is (2-(-1)=2 + 1=3). Since we want to know how many units below (g(x))'s (y) - intercept is (f(x))'s (y) - intercept, we calculate (|2-(-1)|).

Answer:

3 units